OpticsTopic #34 of 35

Reflection and Mirrors

Law of reflection, plane and curved mirrors, and image formation.

Overview

Reflection occurs when light bounces off a surface. Mirrors use reflection to form images. Understanding mirror geometry is fundamental to optics.

Law of Reflection

θi=θr\theta_i = \theta_r

Where:

  • θi\theta_i = angle of incidence (from normal)
  • θr\theta_r = angle of reflection (from normal)

The incident ray, reflected ray, and normal all lie in the same plane.

Types of Reflection

Specular Reflection

  • From smooth surfaces
  • Parallel rays remain parallel
  • Produces clear images (mirrors)

Diffuse Reflection

  • From rough surfaces
  • Parallel rays scatter in many directions
  • Allows us to see non-luminous objects

Plane Mirrors

Image Characteristics

  • Virtual (behind mirror)
  • Same size as object
  • Same distance behind mirror as object is in front
  • Laterally inverted (left-right reversed)
  • Upright

Image Location

di=dod_i = -d_o

(Negative indicates virtual image)

Magnification

m=1m = 1

Spherical Mirrors

Key Points

  • Center of Curvature (C): Center of the sphere
  • Radius of Curvature (R): Radius of the sphere
  • Vertex (V): Point where principal axis meets mirror
  • Principal Axis: Line through C and V
  • Focal Point (F): Where parallel rays converge/appear to diverge from

Focal Length

f=R2f = \frac{R}{2}

Mirror Equation

1do+1di=1f\frac{1}{d_o} + \frac{1}{d_i} = \frac{1}{f}

Where:

  • dod_o = object distance (positive if in front)
  • did_i = image distance (positive if in front for real image)
  • ff = focal length

Magnification

m=hiho=didom = \frac{h_i}{h_o} = -\frac{d_i}{d_o}

Where:

  • hih_i = image height
  • hoh_o = object height
  • m>0m > 0: upright image
  • m<0m < 0: inverted image
  • m>1\lvert m \rvert > 1: enlarged
  • m<1\lvert m \rvert < 1: diminished

Concave Mirrors

f>0f > 0 (focal point in front of mirror)

Object Location and Image

Object PositionImage PositionImage Type
Beyond CBetween C and FReal, inverted, diminished
At CAt CReal, inverted, same size
Between C and FBeyond CReal, inverted, enlarged
At FAt infinity
Inside FBehind mirrorVirtual, upright, enlarged

Convex Mirrors

f<0f < 0 (focal point behind mirror)

Image Characteristics

  • Always virtual
  • Always upright
  • Always diminished
  • Located between F and V (behind mirror)

Applications: security mirrors, car side mirrors

Ray Diagrams

Rules for Drawing Rays (Concave Mirror)

  1. Parallel ray → reflects through F
  2. Ray through F → reflects parallel
  3. Ray through C → reflects back through C
  4. Ray to vertex → reflects at equal angle

Rules for Convex Mirror

  1. Parallel ray → reflects as if from F
  2. Ray toward F → reflects parallel
  3. Ray toward C → reflects back toward C

Examples

Example 1: Plane Mirror

An object is 30 cm in front of a plane mirror. Find image location.

di=do=30 cm (30 cm behind mirror)d_i = -d_o = -30 \text{ cm (30 cm behind mirror)} m=1 (same size)m = 1 \text{ (same size)}

Example 2: Concave Mirror - Real Image

A concave mirror (f=15f = 15 cm) has an object at do=45d_o = 45 cm.

1di=1f1do=115145=345145=245\frac{1}{d_i} = \frac{1}{f} - \frac{1}{d_o} = \frac{1}{15} - \frac{1}{45} = \frac{3}{45} - \frac{1}{45} = \frac{2}{45} di=22.5 cm (real image)d_i = 22.5 \text{ cm (real image)} m=dido=22.545=0.5 (inverted, diminished)m = -\frac{d_i}{d_o} = -\frac{22.5}{45} = -0.5 \text{ (inverted, diminished)}

Example 3: Concave Mirror - Virtual Image

Same mirror, object at do=10d_o = 10 cm (inside focal point).

1di=115110=230330=130\frac{1}{d_i} = \frac{1}{15} - \frac{1}{10} = \frac{2}{30} - \frac{3}{30} = -\frac{1}{30} di=30 cm (virtual, behind mirror)d_i = -30 \text{ cm (virtual, behind mirror)} m=3010=3 (upright, magnified)m = -\frac{-30}{10} = 3 \text{ (upright, magnified)}

Example 4: Convex Mirror

A convex mirror (f=20f = -20 cm) has an object at do=60d_o = 60 cm.

1di=1f1do=120160=360160=460\frac{1}{d_i} = \frac{1}{f} - \frac{1}{d_o} = -\frac{1}{20} - \frac{1}{60} = -\frac{3}{60} - \frac{1}{60} = -\frac{4}{60} di=15 cm (virtual, behind mirror)d_i = -15 \text{ cm (virtual, behind mirror)} m=1560=0.25 (upright, diminished)m = -\frac{-15}{60} = 0.25 \text{ (upright, diminished)}

Example 5: Finding Focal Length

An object 40 cm from a concave mirror produces an image at 120 cm.

1f=1do+1di=140+1120=3120+1120=4120\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} = \frac{1}{40} + \frac{1}{120} = \frac{3}{120} + \frac{1}{120} = \frac{4}{120} f=30 cmf = 30 \text{ cm} R=2f=60 cmR = 2f = 60 \text{ cm}

Example 6: Required Mirror

Design a mirror to produce an image 3× the size of the object, with object at 10 cm.

For real image (inverted): m=3m = -3

di=m×do=3×10=30 cmd_i = -m \times d_o = 3 \times 10 = 30 \text{ cm} 1f=110+130=430\frac{1}{f} = \frac{1}{10} + \frac{1}{30} = \frac{4}{30} f=7.5 cm (concave mirror, R=15 cm)f = 7.5 \text{ cm (concave mirror, } R = 15 \text{ cm)}

Sign Convention Summary

QuantityPositiveNegative
dod_oObject in frontObject behind
did_iImage in front (real)Image behind (virtual)
ffConcave mirrorConvex mirror
mmUpright imageInverted image
RRConcaveConvex