MechanicsTopic #4 of 35

Friction

Static and kinetic friction, coefficients of friction, and applications.

Overview

Friction is a force that opposes the relative motion or tendency of motion between two surfaces in contact.

Types of Friction

Static Friction (fsf_s)

Friction between surfaces that are not moving relative to each other.

fsμsNf_s \leq \mu_s N

  • Maximum static friction: fs,max=μsNf_{s,\max} = \mu_s N
  • Acts to prevent motion from starting
  • Can take any value from 0 to μsN\mu_s N
  • Direction: opposite to the applied force

Kinetic Friction (fkf_k)

Friction between surfaces that are sliding relative to each other.

fk=μkNf_k = \mu_k N

  • Constant magnitude (independent of speed)
  • Direction: opposite to the direction of motion
  • Generally μk<μs\mu_k < \mu_s (easier to keep moving than to start)

Coefficients of Friction

Surface Pairμs\mu_sμk\mu_k
Steel on steel0.740.57
Rubber on concrete (dry)1.00.8
Wood on wood0.50.3
Ice on ice0.10.03
Teflon on steel0.040.04

Key Properties

  • Friction is independent of contact area
  • Friction is proportional to normal force
  • Kinetic friction is approximately independent of velocity
  • μs>μk\mu_s > \mu_k for most materials

Friction on a Horizontal Surface

For an object on a horizontal surface with applied force FF:

At rest (static friction):

fs=F(if F<μsN)f_s = F \quad \text{(if } F < \mu_s N\text{)}

fs=μsN(maximum, about to move)f_s = \mu_s N \quad \text{(maximum, about to move)}

Moving (kinetic friction):

fk=μkNf_k = \mu_k N

Normal force on horizontal surface:

N=mg(no other vertical forces)N = mg \quad \text{(no other vertical forces)}

Friction on an Inclined Plane

For an angle θ\theta from horizontal:

N=mgcosθN = mg\cos\theta

Component of weight parallel to incline:

W=mgsinθW_{\parallel} = mg\sin\theta

Static friction (not sliding):

fs=mgsinθ(if θ<θmax)f_s = mg\sin\theta \quad \text{(if } \theta < \theta_{\max}\text{)}

Maximum angle before sliding:

tan(θmax)=μs\tan(\theta_{\max}) = \mu_s

Kinetic friction (sliding):

fk=μkmgcosθf_k = \mu_k mg\cos\theta

Acceleration down the incline:

a=g(sinθμkcosθ)a = g(\sin\theta - \mu_k\cos\theta)

Rolling Friction

Much smaller than sliding friction:

fr=μrNf_r = \mu_r N

Where μr\mu_r is typically much smaller than μk\mu_k

Examples

Example 1: Box on Floor

A 50 kg box on a floor (μs=0.5\mu_s = 0.5, μk=0.4\mu_k = 0.4). What force is needed to start moving it? What acceleration once moving with 300 N force?

fs,max=μsmg=0.5×50×9.8=245 N (force to start)f_{s,\max} = \mu_s mg = 0.5 \times 50 \times 9.8 = 245 \text{ N (force to start)}

Once moving:

fk=μkmg=0.4×50×9.8=196 Nf_k = \mu_k mg = 0.4 \times 50 \times 9.8 = 196 \text{ N}

F=Ffk=300196=104 N\sum F = F - f_k = 300 - 196 = 104 \text{ N}

a=10450=2.08 m/s2a = \frac{104}{50} = 2.08 \text{ m/s}^2

Example 2: Inclined Plane

A block on a 25° incline (μk=0.2\mu_k = 0.2). Find acceleration.

a=g(sin25°μkcos25°)a = g(\sin 25° - \mu_k\cos 25°)

a=9.8(0.4230.2×0.906)a = 9.8(0.423 - 0.2 \times 0.906)

a=9.8(0.4230.181)=2.37 m/s2a = 9.8(0.423 - 0.181) = 2.37 \text{ m/s}^2

Example 3: Critical Angle

Find the maximum angle at which a block will remain stationary (μs=0.6\mu_s = 0.6).

tan(θmax)=μs=0.6\tan(\theta_{\max}) = \mu_s = 0.6

θmax=tan1(0.6)=31°\theta_{\max} = \tan^{-1}(0.6) = 31°

Motion with Friction

Stopping Distance

For initial velocity v0v_0 on a horizontal surface:

fk=μkmg=maf_k = \mu_k mg = ma

a=μkga = -\mu_k g

Stopping distance: d=v022μkg\text{Stopping distance: } d = \frac{v_0^2}{2\mu_k g}

Connected Objects

For two objects connected, friction on each object must be considered separately based on its normal force.

Important Notes

  • Friction always opposes relative motion
  • Static friction is a response force (adjusts as needed)
  • Normal force is not always equal to weight
  • Friction converts kinetic energy to thermal energy