Oscillations & WavesTopic #16 of 35

Doppler Effect

Frequency shifts due to relative motion of source and observer.

Overview

The Doppler effect is the change in observed frequency (or wavelength) of a wave when there is relative motion between the source and observer.

Basic Concept

  • When source approaches observer: frequency increases (higher pitch)
  • When source moves away: frequency decreases (lower pitch)
  • Same applies when observer moves toward or away from source

General Formula

f=f×v±vovvsf' = f \times \frac{v \pm v_o}{v \mp v_s}

Where:

  • ff' = observed frequency
  • ff = source frequency
  • vv = wave speed in medium
  • vov_o = observer velocity
  • vsv_s = source velocity

Sign Convention

  • Upper signs: approaching
  • Lower signs: receding
  • Observer moving toward source: + in numerator
  • Source moving toward observer: − in denominator

Special Cases

Stationary Observer, Moving Source

Source approaching:

f=f×vvvsf' = f \times \frac{v}{v - v_s}

Source receding:

f=f×vv+vsf' = f \times \frac{v}{v + v_s}

Stationary Source, Moving Observer

Observer approaching:

f=f×v+vovf' = f \times \frac{v + v_o}{v}

Observer receding:

f=f×vvovf' = f \times \frac{v - v_o}{v}

Both Moving (Same Direction)

Source following observer:

f=f×vvovvsf' = f \times \frac{v - v_o}{v - v_s}

Source ahead, observer behind:

f=f×v+vov+vsf' = f \times \frac{v + v_o}{v + v_s}

Wavelength Changes

The observed wavelength:

λ=vf=λ×vvsv±vo\lambda' = \frac{v}{f'} = \lambda \times \frac{v \mp v_s}{v \pm v_o}

For stationary observer, moving source:

λ=λvvsv(approaching)\lambda' = \lambda\frac{v - v_s}{v} \quad \text{(approaching)} λ=λv+vsv(receding)\lambda' = \lambda\frac{v + v_s}{v} \quad \text{(receding)}

Doppler Effect for Light

For electromagnetic waves (where v=cv = c):

Relativistic Formula

f=f×cvrelc+vrelf' = f \times \sqrt{\frac{c - v_{\text{rel}}}{c + v_{\text{rel}}}}

For vcv \ll c (non-relativistic approximation):

ff×(1vrelc)(receding)f' \approx f \times \left(1 - \frac{v_{\text{rel}}}{c}\right) \quad \text{(receding)} ff×(1+vrelc)(approaching)f' \approx f \times \left(1 + \frac{v_{\text{rel}}}{c}\right) \quad \text{(approaching)}

Redshift and Blueshift

  • Redshift: Source moving away → lower frequency, longer wavelength
  • Blueshift: Source approaching → higher frequency, shorter wavelength

Redshift Parameter

z=λobservedλemittedλemitted=Δλλz = \frac{\lambda_{\text{observed}} - \lambda_{\text{emitted}}}{\lambda_{\text{emitted}}} = \frac{\Delta\lambda}{\lambda}

For receding source:

z=vc(for vc)z = \frac{v}{c} \quad \text{(for } v \ll c\text{)}

Shock Waves

When source moves faster than wave speed (vs>vv_s > v):

Mach Number

M=vsvM = \frac{v_s}{v}

Shock Wave Angle

sin(θ)=vvs=1M\sin(\theta) = \frac{v}{v_s} = \frac{1}{M}
  • M<1M < 1: Subsonic
  • M=1M = 1: Sonic (sound barrier)
  • M>1M > 1: Supersonic (sonic boom)

Examples

Example 1: Car Horn

A car horn (f=400f = 400 Hz) approaches at 30 m/s. Find observed frequency (v=343v = 343 m/s).

f=f×vvvs=400×34334330=400×343313=438 Hzf' = f \times \frac{v}{v - v_s} = 400 \times \frac{343}{343 - 30} = 400 \times \frac{343}{313} = 438 \text{ Hz}

Example 2: Police Siren

A police car (siren at 1000 Hz) moves at 40 m/s toward a stationary observer, then passes.

Approaching:

f=1000×34334340=1133 Hzf' = 1000 \times \frac{343}{343 - 40} = 1133 \text{ Hz}

Receding:

f=1000×343343+40=896 Hzf' = 1000 \times \frac{343}{343 + 40} = 896 \text{ Hz}

Frequency change: 1133896=2371133 - 896 = 237 Hz

Example 3: Moving Observer

A person runs at 5 m/s toward a stationary 500 Hz source.

f=500×343+5343=507 Hzf' = 500 \times \frac{343 + 5}{343} = 507 \text{ Hz}

Example 4: Both Moving

A train (500 Hz whistle) moves at 20 m/s toward a car moving at 15 m/s toward the train.

f=500×343+1534320=500×358323=554 Hzf' = 500 \times \frac{343 + 15}{343 - 20} = 500 \times \frac{358}{323} = 554 \text{ Hz}

Example 5: Sonic Boom

A jet flies at Mach 2.5. Find the shock wave angle.

sin(θ)=1M=12.5=0.4\sin(\theta) = \frac{1}{M} = \frac{1}{2.5} = 0.4 θ=sin1(0.4)=23.6°\theta = \sin^{-1}(0.4) = 23.6°

Example 6: Galaxy Redshift

A galaxy shows hydrogen line at 680 nm (lab value: 656 nm). Find recession velocity.

z=Δλλ=680656656=0.0366z = \frac{\Delta\lambda}{\lambda} = \frac{680 - 656}{656} = 0.0366 v=zc=0.0366×3×108=1.1×107 m/sv = zc = 0.0366 \times 3 \times 10^8 = 1.1 \times 10^7 \text{ m/s}

Applications

  • Radar speed guns: Police use Doppler radar to measure vehicle speed
  • Medical ultrasound: Doppler imaging for blood flow
  • Astronomy: Measuring stellar velocities and cosmic expansion
  • Weather radar: Tracking storm movements