Overview
A collision is a brief interaction between two or more objects. Momentum is always conserved in collisions (assuming no external forces), but kinetic energy may or may not be conserved.
Types of Collisions
Elastic Collision
- Kinetic energy is conserved
- Momentum is conserved
- Objects bounce off each other
- Examples: billiard balls, atomic collisions
Inelastic Collision
- Kinetic energy is NOT conserved (some is lost)
- Momentum is conserved
- Some energy converted to heat, sound, deformation
- Most real collisions are inelastic
Perfectly Inelastic Collision
- Maximum kinetic energy loss
- Objects stick together after collision
- Momentum is conserved
- Final velocity is the same for both objects
Conservation Laws for Collisions
Momentum (Always Conserved)
m1v1i+m2v2i=m1v1f+m2v2f
Kinetic Energy (Elastic Only)
21m1v1i2+21m2v2i2=21m1v1f2+21m2v2f2
Elastic Collision Formulas (1D)
For two objects with m1 moving at v1i hitting stationary m2:
v1f=m1+m2m1−m2×v1i
v2f=m1+m22m1×v1i
Special Cases
Equal masses (m1=m2):
v1f=0,v2f=v1i
Objects exchange velocities!
Heavy hitting light (m1≫m2):
v1f≈v1i,v2f≈2v1i
Light hitting heavy (m1≪m2):
v1f≈−v1i,v2f≈0
Perfectly Inelastic Collision
Objects stick together:
m1v1i+m2v2i=(m1+m2)vf
vf=m1+m2m1v1i+m2v2i
Energy Lost
ΔKE=KEf−KEi
ΔKE=21(m1+m2)vf2−[21m1v1i2+21m2v2i2]
For one object initially at rest:
Fraction lost=m1+m2m2
Coefficient of Restitution
Measures "bounciness" of a collision:
e=v1i−v2iv2f−v1f=relative speed beforerelative speed after
| Type | e value |
|---|
| Perfectly elastic | e=1 |
| Partially inelastic | 0<e<1 |
| Perfectly inelastic | e=0 |
Two-Dimensional Collisions
Apply conservation of momentum in each direction:
x-direction:
m1v1xi+m2v2xi=m1v1xf+m2v2xf
y-direction:
m1v1yi+m2v2yi=m1v1yf+m2v2yf
For elastic 2D collision:
21m1v1i2+21m2v2i2=21m1v1f2+21m2v2f2
Center of Mass
Position of center of mass:
xcm=m1+m2m1x1+m2x2
Velocity of center of mass:
vcm=m1+m2m1v1+m2v2=mtotalptotal
Key property: Center of mass velocity is unchanged by collision (in absence of external forces)
Examples
Example 1: Elastic Collision
A 2 kg ball moving at 5 m/s hits a stationary 3 kg ball elastically.
v1f=2+32−3×5=−1 m/s
v2f=2+32(2)×5=4 m/s
Example 2: Perfectly Inelastic
A 1500 kg car at 20 m/s rear-ends a 1000 kg car at 10 m/s. They lock together.
vf=1500+10001500×20+1000×10=250040000=16 m/s
Energy lost:
KEi=21(1500)(20)2+21(1000)(10)2=350,000 J
KEf=21(2500)(16)2=320,000 J
ΔKE=−30,000 J (lost to deformation, heat)
Example 3: Ballistic Pendulum
A bullet (m=10 g, v=400 m/s) embeds in a block (M=2 kg) on a string. Find max height.
Step 1 - Collision (momentum conserved):
mv=(m+M)vf
vf=0.01+20.01×400=1.99 m/s
Step 2 - Swing up (energy conserved):
21(m+M)vf2=(m+M)gh
h=2gvf2=2×9.8(1.99)2=0.20 m
Problem-Solving Strategy
- Identify the type of collision
- Define the system and check for external forces
- Apply conservation of momentum
- If elastic, also apply conservation of kinetic energy
- Solve the equations simultaneously if needed