Integration TechniquesTopic #24 of 32

Trigonometric Integrals

Techniques for integrating powers and products of trig functions.

Powers of Sine and Cosine

sinn(x)cosm(x)dx\int \sin^n(x) \cos^m(x) \, dx

Case 1: n is odd (n=2k+1n = 2k + 1)

Save one sin(x)\sin(x) for dudu, convert rest using sin2(x)=1cos2(x)\sin^2(x) = 1 - \cos^2(x):

sin2k+1(x)cosm(x)dx=(1cos2x)kcosm(x)sin(x)dx\int \sin^{2k+1}(x) \cos^m(x) \, dx = \int (1-\cos^2 x)^k \cos^m(x) \sin(x) \, dx

Let u=cos(x)u = \cos(x), du=sin(x)dxdu = -\sin(x) \, dx

Case 2: m is odd (m=2k+1m = 2k + 1)

Save one cos(x)\cos(x) for dudu, convert rest using cos2(x)=1sin2(x)\cos^2(x) = 1 - \sin^2(x):

sinn(x)cos2k+1(x)dx=sinn(x)(1sin2x)kcos(x)dx\int \sin^n(x) \cos^{2k+1}(x) \, dx = \int \sin^n(x) (1-\sin^2 x)^k \cos(x) \, dx

Let u=sin(x)u = \sin(x), du=cos(x)dxdu = \cos(x) \, dx

Case 3: Both n and m are even

Use half-angle formulas:

sin2(x)=1cos(2x)2\sin^2(x) = \frac{1 - \cos(2x)}{2}

cos2(x)=1+cos(2x)2\cos^2(x) = \frac{1 + \cos(2x)}{2}

sin(x)cos(x)=sin(2x)2\sin(x)\cos(x) = \frac{\sin(2x)}{2}

Powers of Tangent and Secant

tann(x)secm(x)dx\int \tan^n(x) \sec^m(x) \, dx

Case 1: m is even (m=2km = 2k)

Save sec2(x)\sec^2(x) for dudu, convert rest using sec2(x)=1+tan2(x)\sec^2(x) = 1 + \tan^2(x):

tann(x)sec2k(x)dx=tann(x)(1+tan2x)k1sec2(x)dx\int \tan^n(x) \sec^{2k}(x) \, dx = \int \tan^n(x) (1+\tan^2 x)^{k-1} \sec^2(x) \, dx

Let u=tan(x)u = \tan(x), du=sec2(x)dxdu = \sec^2(x) \, dx

Case 2: n is odd (n=2k+1n = 2k + 1)

Save sec(x)tan(x)\sec(x)\tan(x) for dudu, convert rest using tan2(x)=sec2(x)1\tan^2(x) = \sec^2(x) - 1:

tan2k+1(x)secm(x)dx=(sec2x1)ksecm1(x)sec(x)tan(x)dx\int \tan^{2k+1}(x) \sec^m(x) \, dx = \int (\sec^2 x-1)^k \sec^{m-1}(x) \sec(x)\tan(x) \, dx

Let u=sec(x)u = \sec(x), du=sec(x)tan(x)dxdu = \sec(x)\tan(x) \, dx

Important Reduction Formulas

sinn(x)dx=sinn1(x)cos(x)n+n1nsinn2(x)dx\int \sin^n(x) \, dx = -\frac{\sin^{n-1}(x)\cos(x)}{n} + \frac{n-1}{n} \int \sin^{n-2}(x) \, dx

cosn(x)dx=cosn1(x)sin(x)n+n1ncosn2(x)dx\int \cos^n(x) \, dx = \frac{\cos^{n-1}(x)\sin(x)}{n} + \frac{n-1}{n} \int \cos^{n-2}(x) \, dx

tann(x)dx=tann1(x)n1tann2(x)dx\int \tan^n(x) \, dx = \frac{\tan^{n-1}(x)}{n-1} - \int \tan^{n-2}(x) \, dx

secn(x)dx=secn2(x)tan(x)n1+n2n1secn2(x)dx\int \sec^n(x) \, dx = \frac{\sec^{n-2}(x)\tan(x)}{n-1} + \frac{n-2}{n-1} \int \sec^{n-2}(x) \, dx

Examples

Example 1: Odd power of sine

sin3(x)dx=sin2(x)sin(x)dx=(1cos2x)sin(x)dx\int \sin^3(x) \, dx = \int \sin^2(x) \cdot \sin(x) \, dx = \int (1-\cos^2 x)\sin(x) \, dx

Let u=cos(x)u = \cos(x), du=sin(x)dxdu = -\sin(x) \, dx

=(1u2)du=u+u33+C=cos(x)+cos3(x)3+C= -\int (1-u^2) \, du = -u + \frac{u^3}{3} + C = -\cos(x) + \frac{\cos^3(x)}{3} + C

Example 2: Both powers even

sin2(x)cos2(x)dx=[sin(x)cos(x)]2dx\int \sin^2(x)\cos^2(x) \, dx = \int [\sin(x)\cos(x)]^2 \, dx

=[sin(2x)2]2dx=14sin2(2x)dx= \int \left[\frac{\sin(2x)}{2}\right]^2 dx = \frac{1}{4} \int \sin^2(2x) \, dx

=141cos(4x)2dx=18[xsin(4x)4]+C= \frac{1}{4} \int \frac{1-\cos(4x)}{2} \, dx = \frac{1}{8}\left[x - \frac{\sin(4x)}{4}\right] + C

Example 3: Even power of secant

sec4(x)dx=sec2(x)sec2(x)dx=(1+tan2x)sec2(x)dx\int \sec^4(x) \, dx = \int \sec^2(x) \cdot \sec^2(x) \, dx = \int (1+\tan^2 x)\sec^2(x) \, dx

Let u=tan(x)u = \tan(x), du=sec2(x)dxdu = \sec^2(x) \, dx

=(1+u2)du=u+u33+C=tan(x)+tan3(x)3+C= \int (1+u^2) \, du = u + \frac{u^3}{3} + C = \tan(x) + \frac{\tan^3(x)}{3} + C

Example 4: Odd power of tangent

tan3(x)dx=tan(x)tan2(x)dx=tan(x)(sec2x1)dx\int \tan^3(x) \, dx = \int \tan(x) \cdot \tan^2(x) \, dx = \int \tan(x)(\sec^2 x - 1) \, dx

=tan(x)sec2(x)dxtan(x)dx= \int \tan(x)\sec^2(x) \, dx - \int \tan(x) \, dx

For first integral, let u=tan(x)u = \tan(x):

=tan2(x)2lnsec(x)+C= \frac{\tan^2(x)}{2} - \ln|\sec(x)| + C

Example 5: Mixed tan and sec

tan3(x)sec3(x)dx\int \tan^3(x)\sec^3(x) \, dx

Save sec(x)tan(x)\sec(x)\tan(x), use tan2=sec21\tan^2 = \sec^2 - 1:

=tan2(x)sec2(x)sec(x)tan(x)dx= \int \tan^2(x)\sec^2(x) \cdot \sec(x)\tan(x) \, dx

=(sec2x1)sec2(x)sec(x)tan(x)dx= \int (\sec^2 x - 1)\sec^2(x) \cdot \sec(x)\tan(x) \, dx

Let u=sec(x)u = \sec(x), du=sec(x)tan(x)dxdu = \sec(x)\tan(x) \, dx

=(u21)u2du=(u4u2)du= \int (u^2 - 1)u^2 \, du = \int (u^4 - u^2) \, du

=u55u33+C=sec5(x)5sec3(x)3+C= \frac{u^5}{5} - \frac{u^3}{3} + C = \frac{\sec^5(x)}{5} - \frac{\sec^3(x)}{3} + C