Powers of Sine and Cosine
∫sinn(x)cosm(x)dx
Case 1: n is odd (n=2k+1)
Save one sin(x) for du, convert rest using sin2(x)=1−cos2(x):
∫sin2k+1(x)cosm(x)dx=∫(1−cos2x)kcosm(x)sin(x)dx
Let u=cos(x), du=−sin(x)dx
Case 2: m is odd (m=2k+1)
Save one cos(x) for du, convert rest using cos2(x)=1−sin2(x):
∫sinn(x)cos2k+1(x)dx=∫sinn(x)(1−sin2x)kcos(x)dx
Let u=sin(x), du=cos(x)dx
Case 3: Both n and m are even
Use half-angle formulas:
sin2(x)=21−cos(2x)
cos2(x)=21+cos(2x)
sin(x)cos(x)=2sin(2x)
Powers of Tangent and Secant
∫tann(x)secm(x)dx
Case 1: m is even (m=2k)
Save sec2(x) for du, convert rest using sec2(x)=1+tan2(x):
∫tann(x)sec2k(x)dx=∫tann(x)(1+tan2x)k−1sec2(x)dx
Let u=tan(x), du=sec2(x)dx
Case 2: n is odd (n=2k+1)
Save sec(x)tan(x) for du, convert rest using tan2(x)=sec2(x)−1:
∫tan2k+1(x)secm(x)dx=∫(sec2x−1)ksecm−1(x)sec(x)tan(x)dx
Let u=sec(x), du=sec(x)tan(x)dx
Important Reduction Formulas
∫sinn(x)dx=−nsinn−1(x)cos(x)+nn−1∫sinn−2(x)dx
∫cosn(x)dx=ncosn−1(x)sin(x)+nn−1∫cosn−2(x)dx
∫tann(x)dx=n−1tann−1(x)−∫tann−2(x)dx
∫secn(x)dx=n−1secn−2(x)tan(x)+n−1n−2∫secn−2(x)dx
Examples
Example 1: Odd power of sine
∫sin3(x)dx=∫sin2(x)⋅sin(x)dx=∫(1−cos2x)sin(x)dx
Let u=cos(x), du=−sin(x)dx
=−∫(1−u2)du=−u+3u3+C=−cos(x)+3cos3(x)+C
Example 2: Both powers even
∫sin2(x)cos2(x)dx=∫[sin(x)cos(x)]2dx
=∫[2sin(2x)]2dx=41∫sin2(2x)dx
=41∫21−cos(4x)dx=81[x−4sin(4x)]+C
Example 3: Even power of secant
∫sec4(x)dx=∫sec2(x)⋅sec2(x)dx=∫(1+tan2x)sec2(x)dx
Let u=tan(x), du=sec2(x)dx
=∫(1+u2)du=u+3u3+C=tan(x)+3tan3(x)+C
Example 4: Odd power of tangent
∫tan3(x)dx=∫tan(x)⋅tan2(x)dx=∫tan(x)(sec2x−1)dx
=∫tan(x)sec2(x)dx−∫tan(x)dx
For first integral, let u=tan(x):
=2tan2(x)−ln∣sec(x)∣+C
Example 5: Mixed tan and sec
∫tan3(x)sec3(x)dx
Save sec(x)tan(x), use tan2=sec2−1:
=∫tan2(x)sec2(x)⋅sec(x)tan(x)dx
=∫(sec2x−1)sec2(x)⋅sec(x)tan(x)dx
Let u=sec(x), du=sec(x)tan(x)dx
=∫(u2−1)u2du=∫(u4−u2)du
=5u5−3u3+C=5sec5(x)−3sec3(x)+C