The Formula
Integration by parts comes from the product rule:
∫udv=uv−∫vdu
Or in function notation:
∫f(x)g′(x)dx=f(x)g(x)−∫f′(x)g(x)dx
Choosing u and dv: LIATE Rule
Choose u in this order of priority:
- Logarithmic functions (lnx, logx)
- Inverse trig functions (arcsin, arctan, etc.)
- Algebraic functions (x2, x, polynomials)
- Trigonometric functions (sin, cos, tan, etc.)
- Exponential functions (ex, 2x)
The remaining part becomes dv.
Steps
- Identify u and dv using LIATE
- Compute du by differentiating u
- Compute v by integrating dv
- Apply the formula: uv−∫vdu
- Evaluate the remaining integral
Special Cases
Tabular Method
For ∫xnexdx or ∫xnsin(x)dx, use tabular integration:
Create columns for derivatives of u and integrals of dv, alternating signs (+,−,+,−,…).
Circular Integration
When integration by parts leads back to the original integral, solve algebraically.
Examples
Example 1: Polynomial × Exponential
∫xexdx
u=x, dv=exdx
du=dx, v=ex
=xex−∫exdx=xex−ex+C=ex(x−1)+C
Example 2: Polynomial × Trigonometric
∫xsin(x)dx
u=x, dv=sin(x)dx
du=dx, v=−cos(x)
=−xcos(x)−∫−cos(x)dx=−xcos(x)+sin(x)+C
Example 3: Logarithmic
∫ln(x)dx
u=ln(x), dv=dx
du=x1dx, v=x
=xln(x)−∫x⋅x1dx=xln(x)−∫1dx
=xln(x)−x+C=x(ln(x)−1)+C
Example 4: Inverse Trig
∫arctan(x)dx
u=arctan(x), dv=dx
du=1+x21dx, v=x
=xarctan(x)−∫1+x2xdx=xarctan(x)−21ln(1+x2)+C
Example 5: Repeated Integration by Parts
∫x2exdx
First application:
u=x2, dv=exdx
=x2ex−∫2xexdx
Second application on ∫2xexdx:
=x2ex−2(xex−ex)+C
=x2ex−2xex+2ex+C=ex(x2−2x+2)+C
Example 6: Circular (Exponential × Trig)
∫exsin(x)dx
First: u=sin(x), dv=exdx
=exsin(x)−∫excos(x)dx
Second: u=cos(x), dv=exdx
=exsin(x)−[excos(x)+∫exsin(x)dx]
Let I=∫exsin(x)dx:
I=exsin(x)−excos(x)−I
2I=ex(sin(x)−cos(x))
I=2ex(sin(x)−cos(x))+C
Example 7: Definite Integral
∫01xexdx=[ex(x−1)]01
=e(1−1)−e0(0−1)=0−(−1)=1