Integration TechniquesTopic #23 of 32

Integration by Parts

Integrating products of functions using the parts formula.

The Formula

Integration by parts comes from the product rule:

∫u dv=uv−∫v du\int u \, dv = uv - \int v \, du

Or in function notation:

∫f(x)g′(x) dx=f(x)g(x)−∫f′(x)g(x) dx\int f(x)g'(x) \, dx = f(x)g(x) - \int f'(x)g(x) \, dx

Choosing u and dv: LIATE Rule

Choose uu in this order of priority:

  1. Logarithmic functions (ln⁡x\ln x, log⁡x\log x)
  2. Inverse trig functions (arcsin⁡\arcsin, arctan⁡\arctan, etc.)
  3. Algebraic functions (x2x^2, xx, polynomials)
  4. Trigonometric functions (sin⁡\sin, cos⁡\cos, tan⁡\tan, etc.)
  5. Exponential functions (exe^x, 2x2^x)

The remaining part becomes dvdv.

Steps

  1. Identify uu and dvdv using LIATE
  2. Compute dudu by differentiating uu
  3. Compute vv by integrating dvdv
  4. Apply the formula: uv−∫v duuv - \int v \, du
  5. Evaluate the remaining integral

Special Cases

Tabular Method

For ∫xnex dx\int x^n e^x \, dx or ∫xnsin⁡(x) dx\int x^n \sin(x) \, dx, use tabular integration:

Create columns for derivatives of uu and integrals of dvdv, alternating signs (+,−,+,−,…)(+, -, +, -, \ldots).

Circular Integration

When integration by parts leads back to the original integral, solve algebraically.

Examples

Example 1: Polynomial × Exponential

∫xex dx\int x e^x \, dx

u=xu = x, dv=ex dxdv = e^x \, dx du=dxdu = dx, v=exv = e^x

=xex−∫ex dx=xex−ex+C=ex(x−1)+C= xe^x - \int e^x \, dx = xe^x - e^x + C = e^x(x - 1) + C

Example 2: Polynomial × Trigonometric

∫xsin⁡(x) dx\int x \sin(x) \, dx

u=xu = x, dv=sin⁡(x) dxdv = \sin(x) \, dx du=dxdu = dx, v=−cos⁡(x)v = -\cos(x)

=−xcos⁡(x)−∫−cos⁡(x) dx=−xcos⁡(x)+sin⁡(x)+C= -x \cos(x) - \int -\cos(x) \, dx = -x \cos(x) + \sin(x) + C

Example 3: Logarithmic

∫ln⁡(x) dx\int \ln(x) \, dx

u=ln⁡(x)u = \ln(x), dv=dxdv = dx du=1xdxdu = \frac{1}{x} dx, v=xv = x

=xln⁡(x)−∫x⋅1x dx=xln⁡(x)−∫1 dx= x \ln(x) - \int x \cdot \frac{1}{x} \, dx = x \ln(x) - \int 1 \, dx

=xln⁡(x)−x+C=x(ln⁡(x)−1)+C= x \ln(x) - x + C = x(\ln(x) - 1) + C

Example 4: Inverse Trig

∫arctan⁡(x) dx\int \arctan(x) \, dx

u=arctan⁡(x)u = \arctan(x), dv=dxdv = dx du=11+x2dxdu = \frac{1}{1+x^2} dx, v=xv = x

=xarctan⁡(x)−∫x1+x2 dx=xarctan⁡(x)−12ln⁡(1+x2)+C= x \arctan(x) - \int \frac{x}{1+x^2} \, dx = x \arctan(x) - \frac{1}{2}\ln(1+x^2) + C

Example 5: Repeated Integration by Parts

∫x2ex dx\int x^2 e^x \, dx

First application: u=x2u = x^2, dv=ex dxdv = e^x \, dx

=x2ex−∫2xex dx= x^2 e^x - \int 2x e^x \, dx

Second application on ∫2xex dx\int 2x e^x \, dx:

=x2ex−2(xex−ex)+C= x^2 e^x - 2(xe^x - e^x) + C

=x2ex−2xex+2ex+C=ex(x2−2x+2)+C= x^2 e^x - 2xe^x + 2e^x + C = e^x(x^2 - 2x + 2) + C

Example 6: Circular (Exponential × Trig)

∫exsin⁡(x) dx\int e^x \sin(x) \, dx

First: u=sin⁡(x)u = \sin(x), dv=ex dxdv = e^x \, dx

=exsin⁡(x)−∫excos⁡(x) dx= e^x \sin(x) - \int e^x \cos(x) \, dx

Second: u=cos⁡(x)u = \cos(x), dv=ex dxdv = e^x \, dx

=exsin⁡(x)−[excos⁡(x)+∫exsin⁡(x) dx]= e^x \sin(x) - \left[e^x \cos(x) + \int e^x \sin(x) \, dx\right]

Let I=∫exsin⁡(x) dxI = \int e^x \sin(x) \, dx:

I=exsin⁡(x)−excos⁡(x)−II = e^x \sin(x) - e^x \cos(x) - I

2I=ex(sin⁡(x)−cos⁡(x))2I = e^x(\sin(x) - \cos(x))

I=ex2(sin⁡(x)−cos⁡(x))+CI = \frac{e^x}{2}(\sin(x) - \cos(x)) + C

Example 7: Definite Integral

∫01xex dx=[ex(x−1)]01\int_0^1 x e^x \, dx = \left[e^x(x - 1)\right]_0^1

=e(1−1)−e0(0−1)=0−(−1)=1= e(1 - 1) - e^0(0 - 1) = 0 - (-1) = 1