LimitsTopic #1 of 32

Limits and Continuity

Understanding limits, one-sided limits, continuity, and the epsilon-delta definition.

Definition of a Limit

The limit of f(x)f(x) as xx approaches aa is LL, written as:

limxaf(x)=L\lim_{x \to a} f(x) = L

This means f(x)f(x) gets arbitrarily close to LL as xx gets close to aa.

One-Sided Limits

Left-Hand Limit

limxaf(x)=L\lim_{x \to a^-} f(x) = L

Right-Hand Limit

limxa+f(x)=L\lim_{x \to a^+} f(x) = L

The limit exists if and only if both one-sided limits exist and are equal.

Limit Laws

Let limxaf(x)=L\lim_{x \to a} f(x) = L and limxag(x)=M\lim_{x \to a} g(x) = M. Then:

LawFormula
Sumlim[f(x)+g(x)]=L+M\lim [f(x) + g(x)] = L + M
Differencelim[f(x)g(x)]=LM\lim [f(x) - g(x)] = L - M
Productlim[f(x)g(x)]=LM\lim [f(x) \cdot g(x)] = L \cdot M
Quotientlim[f(x)/g(x)]=L/M\lim [f(x)/g(x)] = L/M, if M0M \neq 0
Powerlim[f(x)]n=Ln\lim [f(x)]^n = L^n
Constantlimc=c\lim c = c
Identitylimx=a\lim x = a

Important Limits

limx0sin(x)x=1\lim_{x \to 0} \frac{\sin(x)}{x} = 1

limx01cos(x)x=0\lim_{x \to 0} \frac{1 - \cos(x)}{x} = 0

limx(1+1x)x=e\lim_{x \to \infty} \left(1 + \frac{1}{x}\right)^x = e

limx0ex1x=1\lim_{x \to 0} \frac{e^x - 1}{x} = 1

Continuity

A function ff is continuous at x=ax = a if:

  1. f(a)f(a) is defined
  2. limxaf(x)\lim_{x \to a} f(x) exists
  3. limxaf(x)=f(a)\lim_{x \to a} f(x) = f(a)

Types of Discontinuities

  • Removable: limit exists but f(a)f(a) is undefined or \neq limit
  • Jump: left and right limits exist but are different
  • Infinite: function approaches ±\pm\infty

Intermediate Value Theorem

If ff is continuous on [a,b][a, b] and kk is between f(a)f(a) and f(b)f(b), then there exists at least one cc in (a,b)(a, b) such that f(c)=kf(c) = k.

Examples

Example 1: Evaluate the limit

limx2x24x2\lim_{x \to 2} \frac{x^2 - 4}{x - 2}

=limx2(x+2)(x2)x2= \lim_{x \to 2} \frac{(x + 2)(x - 2)}{x - 2}

=limx2(x+2)=4= \lim_{x \to 2} (x + 2) = 4

Example 2: One-sided limits

For f(x)=xxf(x) = \frac{|x|}{x}:

  • limx0f(x)=1\lim_{x \to 0^-} f(x) = -1 (from the left)
  • limx0+f(x)=1\lim_{x \to 0^+} f(x) = 1 (from the right)
  • Limit does not exist at x=0x = 0