DerivativesTopic #2 of 32

Definition of the Derivative

The derivative as a limit, instantaneous rate of change, and tangent line slope.

Limit Definition

The derivative of ff at xx is defined as:

f′(x)=lim⁡h→0f(x+h)−f(x)hf'(x) = \lim_{h \to 0} \frac{f(x + h) - f(x)}{h}

Alternative form:

f′(a)=lim⁡x→af(x)−f(a)x−af'(a) = \lim_{x \to a} \frac{f(x) - f(a)}{x - a}

Notation

The derivative can be written in several ways:

NotationRead as
f′(x)f'(x)"f prime of x"
dydx\frac{dy}{dx}"dy dx" or "derivative of y with respect to x"
ddx[f(x)]\frac{d}{dx}[f(x)]"d dx of f of x"
Df(x)Df(x)"D of f of x"
y˙\dot{y}"y dot" (Newton's notation)

Geometric Interpretation

The derivative f′(a)f'(a) represents:

  • The slope of the tangent line to y=f(x)y = f(x) at x=ax = a
  • The instantaneous rate of change of ff at x=ax = a

Tangent Line Equation

The tangent line to y=f(x)y = f(x) at point (a,f(a))(a, f(a)):

y−f(a)=f′(a)(x−a)y - f(a) = f'(a)(x - a)

or

y=f(a)+f′(a)(x−a)y = f(a) + f'(a)(x - a)

Physical Interpretation

If s(t)s(t) represents position at time tt:

  • s′(t)=v(t)s'(t) = v(t) = velocity
  • s′′(t)=v′(t)=a(t)s''(t) = v'(t) = a(t) = acceleration

Differentiability

A function ff is differentiable at x=ax = a if f′(a)f'(a) exists.

Conditions for Differentiability

  • ff must be continuous at aa (necessary but not sufficient)
  • The left and right derivatives must exist and be equal

Non-Differentiable Points

A function is NOT differentiable at:

  • Corners (sharp points)
  • Cusps
  • Vertical tangents
  • Discontinuities

Examples

Example 1: Using the definition

Find f′(x)f'(x) for f(x)=x2f(x) = x^2:

f′(x)=lim⁡h→0(x+h)2−x2hf'(x) = \lim_{h \to 0} \frac{(x + h)^2 - x^2}{h}

=lim⁡h→0x2+2xh+h2−x2h= \lim_{h \to 0} \frac{x^2 + 2xh + h^2 - x^2}{h}

=lim⁡h→02xh+h2h= \lim_{h \to 0} \frac{2xh + h^2}{h}

=lim⁡h→0(2x+h)=2x= \lim_{h \to 0} (2x + h) = 2x

Example 2: Tangent line

Find the tangent line to f(x)=x3f(x) = x^3 at x=2x = 2:

  • f(2)=8f(2) = 8
  • f′(x)=3x2f'(x) = 3x^2, so f′(2)=12f'(2) = 12

Tangent line: y−8=12(x−2)y - 8 = 12(x - 2), or y=12x−16y = 12x - 16