TrigonometryTopic #25 of 32

Right Triangle Trigonometry

SOH-CAH-TOA, special right triangles (30-60-90 and 45-45-90).

Basic Definitions (SOH-CAH-TOA)

For a right triangle with acute angle θ\theta:

sinθ=OppositeHypotenuse(SOH)\sin\theta = \frac{\text{Opposite}}{\text{Hypotenuse}} \quad \text{(SOH)}

cosθ=AdjacentHypotenuse(CAH)\cos\theta = \frac{\text{Adjacent}}{\text{Hypotenuse}} \quad \text{(CAH)}

tanθ=OppositeAdjacent(TOA)\tan\theta = \frac{\text{Opposite}}{\text{Adjacent}} \quad \text{(TOA)}

And the reciprocals:

cscθ=HypotenuseOpposite=1sinθ\csc\theta = \frac{\text{Hypotenuse}}{\text{Opposite}} = \frac{1}{\sin\theta}

secθ=HypotenuseAdjacent=1cosθ\sec\theta = \frac{\text{Hypotenuse}}{\text{Adjacent}} = \frac{1}{\cos\theta}

cotθ=AdjacentOpposite=1tanθ\cot\theta = \frac{\text{Adjacent}}{\text{Opposite}} = \frac{1}{\tan\theta}

Pythagorean Theorem

For a right triangle with legs aa and bb, and hypotenuse cc:

a2+b2=c2a^2 + b^2 = c^2

45-45-90 Triangle (Isosceles Right Triangle)

Angles: 45°45°, 45°45°, 90°90°

SideRatio
Leg11
Leg11
Hypotenuse2\sqrt{2}

If leg =a= a:

  • Leg =a= a
  • Leg =a= a
  • Hypotenuse =a2= a\sqrt{2}

If hypotenuse =c= c:

  • Each leg =c2=c22= \frac{c}{\sqrt{2}} = \frac{c\sqrt{2}}{2}

Trig Values for 45°

FunctionValue
sin45°\sin 45°220.707\frac{\sqrt{2}}{2} \approx 0.707
cos45°\cos 45°220.707\frac{\sqrt{2}}{2} \approx 0.707
tan45°\tan 45°11
csc45°\csc 45°2\sqrt{2}
sec45°\sec 45°2\sqrt{2}
cot45°\cot 45°11

30-60-90 Triangle

Angles: 30°30°, 60°60°, 90°90°

SideRatioPosition
Short leg11Opposite 30°30°
Long leg3\sqrt{3}Opposite 60°60°
Hypotenuse22Opposite 90°90°

If short leg =a= a:

  • Short leg (opp 30°30°) =a= a
  • Long leg (opp 60°60°) =a3= a\sqrt{3}
  • Hypotenuse =2a= 2a

Trig Values for 30°

FunctionValue
sin30°\sin 30°12=0.5\frac{1}{2} = 0.5
cos30°\cos 30°320.866\frac{\sqrt{3}}{2} \approx 0.866
tan30°\tan 30°330.577\frac{\sqrt{3}}{3} \approx 0.577
csc30°\csc 30°22
sec30°\sec 30°233\frac{2\sqrt{3}}{3}
cot30°\cot 30°3\sqrt{3}

Trig Values for 60°

FunctionValue
sin60°\sin 60°320.866\frac{\sqrt{3}}{2} \approx 0.866
cos60°\cos 60°12=0.5\frac{1}{2} = 0.5
tan60°\tan 60°31.732\sqrt{3} \approx 1.732
csc60°\csc 60°233\frac{2\sqrt{3}}{3}
sec60°\sec 60°22
cot60°\cot 60°33\frac{\sqrt{3}}{3}

Solving Right Triangles

Given information, find all sides and angles.

Given Two Sides

  1. Use Pythagorean theorem for third side
  2. Use trig ratios for angles

Given One Side and One Acute Angle

  1. Use trig ratios to find other sides
  2. Subtract from 90°90° for other acute angle

Applications

Angle of Elevation

Angle measured upward from horizontal.

Angle of Depression

Angle measured downward from horizontal.

Key insight: Angle of elevation from A to B equals angle of depression from B to A (alternate interior angles).

Quick Reference: Special Angle Values

Anglesin\sincos\costan\tan
0°001100
30°30°12\frac{1}{2}32\frac{\sqrt{3}}{2}33\frac{\sqrt{3}}{3}
45°45°22\frac{\sqrt{2}}{2}22\frac{\sqrt{2}}{2}11
60°60°32\frac{\sqrt{3}}{2}12\frac{1}{2}3\sqrt{3}
90°90°1100undefined